Implement contravariant type checking for procedure types
Consider list types A = (list foo) and B = (list bar). In functions where list of type A is expected you can give list of type B if bar is more specific (or of same type) than foo. For example foo could be (or fixnum string) and bar be fixnum.
Now consider procedure types F = (t1 -> *) and H = (t2 -> *). In functions where a function parameter of type F is expected you can give function of type H if t2 is more general than t1. For example, if t2 is (or fixnum string) and t1 is string.
Here is an example where the scrutinizer can't tell anything is wrong:
(define-type dog (vector string))
(define-type cat (vector fixnum string))
(define-type animal (or cat dog))
(: make-dog (-> dog))
(define (make-dog)
(vector "woof"))
(define (dog? a)
(= 1 (vector-length a)))
(: make-cat (-> cat))
(define (make-cat)
(vector 0 "meow"))
(define (cat? a)
(= 2 (vector-length a)))
(: animal-print (animal -> *))
(define (animal-print a)
(cond
[(dog? a) (dog-print a)]
[(cat? a) (cat-print a)]))
(: dog-print (dog -> *))
(define (dog-print d)
(print "dog says " (vector-ref d 0)))
(: cat-print (cat -> *))
(define (cat-print c)
(print "cat says " (vector-ref c 1)))
(: apply-printer (forall (T) ((T -> *) T -> *)))
(define (apply-printer pr e)
(pr e))
(: print-animals ((animal -> *) (list-of animal) -> *))
(define (print-animals pr animals)
(for-each pr animals))
;; (apply-printer cat-print (make-dog)) ; warns ok
;; (print-animals animal-print (list (make-dog) (make-cat))) ; works ok
;; doesn't warn, but fails at runtime
(print-animals cat-print (list (make-cat) (make-dog)))
;; $ csc -O3 vector-contravariant.scm && ./vector-contravariant
;; cat says meow
;;
;; Error: (vector-ref) out of range
;; #("woof")
;; 1
;;
;; Call history:
;;
;; vector-contravariant.scm:44: print-animals
;; vector-contravariant.scm:36: g30
;; vector-contravariant.scm:29: print
;; vector-contravariant.scm:36: g30
Getting ready for 5.1, moving tickets which won't make it in to 5.2.